3x^2-34x-289=0

Solution for 3x^2-34x-289=0 equation:

3x^2-34x-289=0

a = 3; b = -34; c = -289;
Δ = b2-4ac
Δ = -342-4·3·(-289)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-68}{2*3}=\frac{-34}{6}
=-5+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+68}{2*3}=\frac{102}{6}
=17
$